Integrand size = 44, antiderivative size = 209 \[ \int \frac {(d+e x)^{3/2} (f+g x)}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx=-\frac {4 \left (c d^2-a e^2\right ) \left (4 a e^2 g-c d (5 e f-d g)\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{15 c^3 d^3 e \sqrt {d+e x}}-\frac {2 \left (4 a e^2 g-c d (5 e f-d g)\right ) \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{15 c^2 d^2 e}+\frac {2 g (d+e x)^{3/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{5 c d e} \]
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Time = 0.13 (sec) , antiderivative size = 209, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.068, Rules used = {808, 670, 662} \[ \int \frac {(d+e x)^{3/2} (f+g x)}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx=-\frac {4 \left (c d^2-a e^2\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2} \left (4 a e^2 g-c d (5 e f-d g)\right )}{15 c^3 d^3 e \sqrt {d+e x}}-\frac {2 \sqrt {d+e x} \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2} \left (4 a e^2 g-c d (5 e f-d g)\right )}{15 c^2 d^2 e}+\frac {2 g (d+e x)^{3/2} \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{5 c d e} \]
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Rule 662
Rule 670
Rule 808
Rubi steps \begin{align*} \text {integral}& = \frac {2 g (d+e x)^{3/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{5 c d e}+\frac {1}{5} \left (5 f-\frac {d g}{e}-\frac {4 a e g}{c d}\right ) \int \frac {(d+e x)^{3/2}}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx \\ & = -\frac {2 \left (4 a e^2 g-c d (5 e f-d g)\right ) \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{15 c^2 d^2 e}+\frac {2 g (d+e x)^{3/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{5 c d e}+\frac {\left (2 \left (d^2-\frac {a e^2}{c}\right ) \left (5 f-\frac {d g}{e}-\frac {4 a e g}{c d}\right )\right ) \int \frac {\sqrt {d+e x}}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx}{15 d} \\ & = -\frac {4 \left (c d^2-a e^2\right ) \left (4 a e^2 g-c d (5 e f-d g)\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{15 c^3 d^3 e \sqrt {d+e x}}-\frac {2 \left (4 a e^2 g-c d (5 e f-d g)\right ) \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{15 c^2 d^2 e}+\frac {2 g (d+e x)^{3/2} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{5 c d e} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 96, normalized size of antiderivative = 0.46 \[ \int \frac {(d+e x)^{3/2} (f+g x)}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx=\frac {2 \sqrt {(a e+c d x) (d+e x)} \left (8 a^2 e^3 g-2 a c d e (5 e f+5 d g+2 e g x)+c^2 d^2 (5 d (3 f+g x)+e x (5 f+3 g x))\right )}{15 c^3 d^3 \sqrt {d+e x}} \]
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Time = 0.54 (sec) , antiderivative size = 113, normalized size of antiderivative = 0.54
method | result | size |
default | \(\frac {2 \sqrt {\left (c d x +a e \right ) \left (e x +d \right )}\, \left (3 e g \,x^{2} c^{2} d^{2}-4 a c d \,e^{2} g x +5 c^{2} d^{3} g x +5 c^{2} d^{2} e f x +8 a^{2} e^{3} g -10 a c \,d^{2} e g -10 a c d \,e^{2} f +15 d^{3} f \,c^{2}\right )}{15 \sqrt {e x +d}\, c^{3} d^{3}}\) | \(113\) |
gosper | \(\frac {2 \left (c d x +a e \right ) \left (3 e g \,x^{2} c^{2} d^{2}-4 a c d \,e^{2} g x +5 c^{2} d^{3} g x +5 c^{2} d^{2} e f x +8 a^{2} e^{3} g -10 a c \,d^{2} e g -10 a c d \,e^{2} f +15 d^{3} f \,c^{2}\right ) \sqrt {e x +d}}{15 c^{3} d^{3} \sqrt {c d e \,x^{2}+a \,e^{2} x +c \,d^{2} x +a d e}}\) | \(131\) |
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Time = 0.30 (sec) , antiderivative size = 141, normalized size of antiderivative = 0.67 \[ \int \frac {(d+e x)^{3/2} (f+g x)}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx=\frac {2 \, {\left (3 \, c^{2} d^{2} e g x^{2} + 5 \, {\left (3 \, c^{2} d^{3} - 2 \, a c d e^{2}\right )} f - 2 \, {\left (5 \, a c d^{2} e - 4 \, a^{2} e^{3}\right )} g + {\left (5 \, c^{2} d^{2} e f + {\left (5 \, c^{2} d^{3} - 4 \, a c d e^{2}\right )} g\right )} x\right )} \sqrt {c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x} \sqrt {e x + d}}{15 \, {\left (c^{3} d^{3} e x + c^{3} d^{4}\right )}} \]
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\[ \int \frac {(d+e x)^{3/2} (f+g x)}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx=\int \frac {\left (d + e x\right )^{\frac {3}{2}} \left (f + g x\right )}{\sqrt {\left (d + e x\right ) \left (a e + c d x\right )}}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 168, normalized size of antiderivative = 0.80 \[ \int \frac {(d+e x)^{3/2} (f+g x)}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx=\frac {2 \, {\left (c^{2} d^{2} e x^{2} + 3 \, a c d^{2} e - 2 \, a^{2} e^{3} + {\left (3 \, c^{2} d^{3} - a c d e^{2}\right )} x\right )} f}{3 \, \sqrt {c d x + a e} c^{2} d^{2}} + \frac {2 \, {\left (3 \, c^{3} d^{3} e x^{3} - 10 \, a^{2} c d^{2} e^{2} + 8 \, a^{3} e^{4} + {\left (5 \, c^{3} d^{4} - a c^{2} d^{2} e^{2}\right )} x^{2} - {\left (5 \, a c^{2} d^{3} e - 4 \, a^{2} c d e^{3}\right )} x\right )} g}{15 \, \sqrt {c d x + a e} c^{3} d^{3}} \]
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Time = 0.31 (sec) , antiderivative size = 346, normalized size of antiderivative = 1.66 \[ \int \frac {(d+e x)^{3/2} (f+g x)}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx=\frac {2 \, e {\left (\frac {15 \, {\left (c^{2} d^{3} f - a c d e^{2} f - a c d^{2} e g + a^{2} e^{3} g\right )} \sqrt {{\left (e x + d\right )} c d e - c d^{2} e + a e^{3}}}{c^{3} d^{3} e} - \frac {2 \, {\left (5 \, \sqrt {-c d^{2} e + a e^{3}} c^{2} d^{3} e f - 5 \, \sqrt {-c d^{2} e + a e^{3}} a c d e^{3} f - \sqrt {-c d^{2} e + a e^{3}} c^{2} d^{4} g - 3 \, \sqrt {-c d^{2} e + a e^{3}} a c d^{2} e^{2} g + 4 \, \sqrt {-c d^{2} e + a e^{3}} a^{2} e^{4} g\right )}}{c^{3} d^{3} e^{2}} + \frac {5 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {3}{2}} c d e^{2} f + 5 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {3}{2}} c d^{2} e g - 10 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {3}{2}} a e^{3} g + 3 \, {\left ({\left (e x + d\right )} c d e - c d^{2} e + a e^{3}\right )}^{\frac {5}{2}} g}{c^{3} d^{3} e^{4}}\right )}}{15 \, {\left | e \right |}} \]
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Time = 12.00 (sec) , antiderivative size = 152, normalized size of antiderivative = 0.73 \[ \int \frac {(d+e x)^{3/2} (f+g x)}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx=\frac {\sqrt {c\,d\,e\,x^2+\left (c\,d^2+a\,e^2\right )\,x+a\,d\,e}\,\left (\frac {\sqrt {d+e\,x}\,\left (16\,g\,a^2\,e^3-20\,g\,a\,c\,d^2\,e-20\,f\,a\,c\,d\,e^2+30\,f\,c^2\,d^3\right )}{15\,c^3\,d^3\,e}+\frac {2\,g\,x^2\,\sqrt {d+e\,x}}{5\,c\,d}+\frac {2\,x\,\sqrt {d+e\,x}\,\left (5\,c\,g\,d^2+5\,c\,f\,d\,e-4\,a\,g\,e^2\right )}{15\,c^2\,d^2\,e}\right )}{x+\frac {d}{e}} \]
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